py/objstr: Don't treat bytes as unicode in str.count.

`b'\xaa \xaa'.count(b'\xaa')` now (correctly) returns 2 instead of 1.

Fixes issue #9404.

This work was funded through GitHub Sponsors.

Signed-off-by: Jim Mussared <jim.mussared@gmail.com>

1 files changed, 7 insertions, 0 deletions

diff --git a/tests/basics/bytes_count.py b/tests/basics/bytes_count.py
index 5fa0730f5..e71f09db0 100644
--- a/tests/basics/bytes_count.py
+++ b/tests/basics/bytes_count.py
@@ -48,6 +48,13 @@ print(b"aaaa".count(b'a', 1, 5))
 print(b"aaaa".count(b'a', -1, 5))
 print(b"abbabba".count(b"abba"))
 
+print(b'\xaa \xaa'.count(b'\xaa'))
+print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'))
+print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 1)
+print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 2)
+print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 1, 3)
+print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 2, 3)
+
 def t():
     return True