diff options
| author | Tom Lane <tgl@sss.pgh.pa.us> | 2022-08-28 10:44:52 -0400 |
|---|---|---|
| committer | Tom Lane <tgl@sss.pgh.pa.us> | 2022-08-28 10:44:52 -0400 |
| commit | ebe2b4097b5a5ce069a60358b1361d2702cac67f (patch) | |
| tree | afc75d1f7204352a078e597a985902d58e321fd8 | |
| parent | 73cbdb7f1944b2ad847fb62d71011b96cd96c8fd (diff) | |
Doc: fix example of recursive query.
Compute total number of sub-parts correctly, per jason@banfelder.net
Simon Riggs
Discussion: https://postgr.es/m/166161184718.1235920.6304070286124217754@wrigleys.postgresql.org
| -rw-r--r-- | doc/src/sgml/queries.sgml | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/doc/src/sgml/queries.sgml b/doc/src/sgml/queries.sgml index 516fbcbf375..1428d99d0f8 100644 --- a/doc/src/sgml/queries.sgml +++ b/doc/src/sgml/queries.sgml @@ -2195,7 +2195,7 @@ SELECT sum(n) FROM t; WITH RECURSIVE included_parts(sub_part, part, quantity) AS ( SELECT sub_part, part, quantity FROM parts WHERE part = 'our_product' UNION ALL - SELECT p.sub_part, p.part, p.quantity + SELECT p.sub_part, p.part, p.quantity * pr.quantity FROM included_parts pr, parts p WHERE p.part = pr.sub_part ) |