1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
|
/*
bitfld-1-1.c from the execute part of the gcc torture tests.
*/
#include <testfwk.h>
#ifdef __SDCC
#pragma std_c89
#endif
/* Copyright 2002 Free Software Foundation, Inc.
Tests correct signedness of operations on bitfields; in particular
that integer promotions are done correctly, including the case when
casts are present.
The C front end was eliding the cast of an unsigned bitfield to
unsigned as a no-op, when in fact it forces a conversion to a
full-width unsigned int. (At the time of writing, the C++ front end
has a different bug; it erroneously promotes the uncast unsigned
bitfield to an unsigned int).
Source: Neil Booth, 25 Jan 2002, based on PR 3325 (and 3326, which
is a different manifestation of the same bug).
*/
extern void abort ();
void
testTortureExecute (void)
{
struct x { signed int i : 7; unsigned int u : 7; } bit;
unsigned int u;
int i;
unsigned int unsigned_result = -13U % 61;
int signed_result = -13 % 61;
bit.u = 61, u = 61;
bit.i = -13, i = -13;
if (i % u != unsigned_result)
ASSERT (0);
if (i % (unsigned int) u != unsigned_result)
ASSERT (0);
/* Somewhat counter-intuitively, bit.u is promoted to an int, making
the operands and result an int. */
if (i % bit.u != signed_result)
ASSERT (0);;
if (bit.i % bit.u != signed_result)
ASSERT (0);
/* But with a cast to unsigned int, the unsigned int is promoted to
itself as a no-op, and the operands and result are unsigned. */
if (i % (unsigned int) bit.u != unsigned_result)
ASSERT (0);
if (bit.i % (unsigned int) bit.u != unsigned_result)
ASSERT (0);
return;
}
|
